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Jiunn Chang2a5b0c842019-06-26 15:07:03 -05001.. _up_doc:
Linus Torvalds1da177e2005-04-16 15:20:36 -07002
Jiunn Chang2a5b0c842019-06-26 15:07:03 -05003RCU on Uniprocessor Systems
4===========================
Linus Torvalds1da177e2005-04-16 15:20:36 -07005
6A common misconception is that, on UP systems, the call_rcu() primitive
Paul E. McKenney240ebbf2009-06-25 09:08:18 -07007may immediately invoke its function. The basis of this misconception
Linus Torvalds1da177e2005-04-16 15:20:36 -07008is that since there is only one CPU, it should not be necessary to
9wait for anything else to get done, since there are no other CPUs for
Jiunn Chang2a5b0c842019-06-26 15:07:03 -050010anything else to be happening on. Although this approach will *sort of*
Linus Torvalds1da177e2005-04-16 15:20:36 -070011work a surprising amount of the time, it is a very bad idea in general.
Paul E. McKenney240ebbf2009-06-25 09:08:18 -070012This document presents three examples that demonstrate exactly how bad
13an idea this is.
Linus Torvalds1da177e2005-04-16 15:20:36 -070014
Linus Torvalds1da177e2005-04-16 15:20:36 -070015Example 1: softirq Suicide
Jiunn Chang2a5b0c842019-06-26 15:07:03 -050016--------------------------
Linus Torvalds1da177e2005-04-16 15:20:36 -070017
18Suppose that an RCU-based algorithm scans a linked list containing
19elements A, B, and C in process context, and can delete elements from
20this same list in softirq context. Suppose that the process-context scan
21is referencing element B when it is interrupted by softirq processing,
22which deletes element B, and then invokes call_rcu() to free element B
23after a grace period.
24
25Now, if call_rcu() were to directly invoke its arguments, then upon return
26from softirq, the list scan would find itself referencing a newly freed
27element B. This situation can greatly decrease the life expectancy of
28your kernel.
29
Paul E. McKenneydd81eca2005-09-10 00:26:24 -070030This same problem can occur if call_rcu() is invoked from a hardware
31interrupt handler.
32
Linus Torvalds1da177e2005-04-16 15:20:36 -070033Example 2: Function-Call Fatality
Jiunn Chang2a5b0c842019-06-26 15:07:03 -050034---------------------------------
Linus Torvalds1da177e2005-04-16 15:20:36 -070035
36Of course, one could avert the suicide described in the preceding example
37by having call_rcu() directly invoke its arguments only if it was called
38from process context. However, this can fail in a similar manner.
39
40Suppose that an RCU-based algorithm again scans a linked list containing
41elements A, B, and C in process contexts, but that it invokes a function
42on each element as it is scanned. Suppose further that this function
43deletes element B from the list, then passes it to call_rcu() for deferred
44freeing. This may be a bit unconventional, but it is perfectly legal
45RCU usage, since call_rcu() must wait for a grace period to elapse.
46Therefore, in this case, allowing call_rcu() to immediately invoke
47its arguments would cause it to fail to make the fundamental guarantee
48underlying RCU, namely that call_rcu() defers invoking its arguments until
49all RCU read-side critical sections currently executing have completed.
50
Jiunn Chang2a5b0c842019-06-26 15:07:03 -050051Quick Quiz #1:
52 Why is it *not* legal to invoke synchronize_rcu() in this case?
Paul E. McKenneydd81eca2005-09-10 00:26:24 -070053
Jiunn Chang2a5b0c842019-06-26 15:07:03 -050054:ref:`Answers to Quick Quiz <answer_quick_quiz_up>`
Paul E. McKenneydd81eca2005-09-10 00:26:24 -070055
56Example 3: Death by Deadlock
Jiunn Chang2a5b0c842019-06-26 15:07:03 -050057----------------------------
Paul E. McKenneydd81eca2005-09-10 00:26:24 -070058
59Suppose that call_rcu() is invoked while holding a lock, and that the
60callback function must acquire this same lock. In this case, if
61call_rcu() were to directly invoke the callback, the result would
62be self-deadlock.
63
64In some cases, it would possible to restructure to code so that
65the call_rcu() is delayed until after the lock is released. However,
66there are cases where this can be quite ugly:
67
681. If a number of items need to be passed to call_rcu() within
69 the same critical section, then the code would need to create
70 a list of them, then traverse the list once the lock was
71 released.
72
732. In some cases, the lock will be held across some kernel API,
74 so that delaying the call_rcu() until the lock is released
75 requires that the data item be passed up via a common API.
76 It is far better to guarantee that callbacks are invoked
77 with no locks held than to have to modify such APIs to allow
78 arbitrary data items to be passed back up through them.
79
80If call_rcu() directly invokes the callback, painful locking restrictions
81or API changes would be required.
82
Jiunn Chang2a5b0c842019-06-26 15:07:03 -050083Quick Quiz #2:
84 What locking restriction must RCU callbacks respect?
Linus Torvalds1da177e2005-04-16 15:20:36 -070085
Jiunn Chang2a5b0c842019-06-26 15:07:03 -050086:ref:`Answers to Quick Quiz <answer_quick_quiz_up>`
Linus Torvalds1da177e2005-04-16 15:20:36 -070087
88Summary
Jiunn Chang2a5b0c842019-06-26 15:07:03 -050089-------
Linus Torvalds1da177e2005-04-16 15:20:36 -070090
Paul E. McKenney240ebbf2009-06-25 09:08:18 -070091Permitting call_rcu() to immediately invoke its arguments breaks RCU,
92even on a UP system. So do not do it! Even on a UP system, the RCU
Jiunn Chang2a5b0c842019-06-26 15:07:03 -050093infrastructure *must* respect grace periods, and *must* invoke callbacks
Paul E. McKenney240ebbf2009-06-25 09:08:18 -070094from a known environment in which no locks are held.
95
Jiunn Chang2a5b0c842019-06-26 15:07:03 -050096Note that it *is* safe for synchronize_rcu() to return immediately on
97UP systems, including PREEMPT SMP builds running on UP systems.
Paul E. McKenney240ebbf2009-06-25 09:08:18 -070098
Jiunn Chang2a5b0c842019-06-26 15:07:03 -050099Quick Quiz #3:
100 Why can't synchronize_rcu() return immediately on UP systems running
101 preemptable RCU?
Linus Torvalds1da177e2005-04-16 15:20:36 -0700102
Jiunn Chang2a5b0c842019-06-26 15:07:03 -0500103.. _answer_quick_quiz_up:
Linus Torvalds1da177e2005-04-16 15:20:36 -0700104
Paul E. McKenneydd81eca2005-09-10 00:26:24 -0700105Answer to Quick Quiz #1:
Jiunn Chang2a5b0c842019-06-26 15:07:03 -0500106 Why is it *not* legal to invoke synchronize_rcu() in this case?
Linus Torvalds1da177e2005-04-16 15:20:36 -0700107
Paul E. McKenneydd81eca2005-09-10 00:26:24 -0700108 Because the calling function is scanning an RCU-protected linked
109 list, and is therefore within an RCU read-side critical section.
110 Therefore, the called function has been invoked within an RCU
111 read-side critical section, and is not permitted to block.
112
113Answer to Quick Quiz #2:
114 What locking restriction must RCU callbacks respect?
115
Jiunn Changacb62582019-06-27 16:01:47 -0500116 Any lock that is acquired within an RCU callback must be acquired
117 elsewhere using an _bh variant of the spinlock primitive.
118 For example, if "mylock" is acquired by an RCU callback, then
119 a process-context acquisition of this lock must use something
120 like spin_lock_bh() to acquire the lock. Please note that
121 it is also OK to use _irq variants of spinlocks, for example,
122 spin_lock_irqsave().
Paul E. McKenneydd81eca2005-09-10 00:26:24 -0700123
124 If the process-context code were to simply use spin_lock(),
125 then, since RCU callbacks can be invoked from softirq context,
126 the callback might be called from a softirq that interrupted
127 the process-context critical section. This would result in
128 self-deadlock.
129
130 This restriction might seem gratuitous, since very few RCU
131 callbacks acquire locks directly. However, a great many RCU
Jiunn Chang2a5b0c842019-06-26 15:07:03 -0500132 callbacks do acquire locks *indirectly*, for example, via
Paul E. McKenneydd81eca2005-09-10 00:26:24 -0700133 the kfree() primitive.
Paul E. McKenney240ebbf2009-06-25 09:08:18 -0700134
135Answer to Quick Quiz #3:
136 Why can't synchronize_rcu() return immediately on UP systems
137 running preemptable RCU?
138
139 Because some other task might have been preempted in the middle
140 of an RCU read-side critical section. If synchronize_rcu()
141 simply immediately returned, it would prematurely signal the
142 end of the grace period, which would come as a nasty shock to
143 that other thread when it started running again.