sctp: only drop the reference on the datamsg after sending a msg
If the chunks are enqueued successfully but sctp_cmd_interpreter()
return err to sctp_sendmsg() (mainly because of no mem), the chunks will
get re-queued, but we are dropping the reference and freeing them.
The fix is to just drop the reference on the datamsg just as it had
succeeded, as:
- if the chunks weren't queued, this is enough to get them freed.
- if they were queued, they will get freed when they finally get out or
discarded.
Signed-off-by: Xin Long <lucien.xin@gmail.com>
Marcelo Ricardo Leitner <marcelo.leitner@gmail.com>
Signed-off-by: Marcelo Ricardo Leitner <marcelo.leitner@gmail.com>
Signed-off-by: David S. Miller <davem@davemloft.net>
diff --git a/net/sctp/socket.c b/net/sctp/socket.c
index bd57300..9b6cc6d 100644
--- a/net/sctp/socket.c
+++ b/net/sctp/socket.c
@@ -1964,15 +1964,13 @@
* breaks.
*/
err = sctp_primitive_SEND(net, asoc, datamsg);
+ sctp_datamsg_put(datamsg);
/* Did the lower layer accept the chunk? */
- if (err) {
- sctp_datamsg_free(datamsg);
+ if (err)
goto out_free;
- }
pr_debug("%s: we sent primitively\n", __func__);
- sctp_datamsg_put(datamsg);
err = msg_len;
if (unlikely(wait_connect)) {