fanotify: Fix the checks in fanotify_fsid_equal
Clang warns:
fs/notify/fanotify/fanotify.c:28:23: warning: self-comparison always
evaluates to true [-Wtautological-compare]
return fsid1->val[0] == fsid1->val[0] && fsid2->val[1] == fsid2->val[1];
^
fs/notify/fanotify/fanotify.c:28:57: warning: self-comparison always
evaluates to true [-Wtautological-compare]
return fsid1->val[0] == fsid1->val[0] && fsid2->val[1] == fsid2->val[1];
^
2 warnings generated.
The intention was clearly to compare val[0] and val[1] in the two
different fsid structs. Fix it otherwise this function always returns
true.
Fixes: afc894c784c8 ("fanotify: Store fanotify handles differently")
Link: https://github.com/ClangBuiltLinux/linux/issues/952
Link: https://lore.kernel.org/r/20200327171030.30625-1-natechancellor@gmail.com
Signed-off-by: Nathan Chancellor <natechancellor@gmail.com>
Reviewed-by: Nick Desaulniers <ndesaulniers@google.com>
Signed-off-by: Jan Kara <jack@suse.cz>
diff --git a/fs/notify/fanotify/fanotify.c b/fs/notify/fanotify/fanotify.c
index 4c1a4eb..5435a40 100644
--- a/fs/notify/fanotify/fanotify.c
+++ b/fs/notify/fanotify/fanotify.c
@@ -25,7 +25,7 @@ static bool fanotify_path_equal(struct path *p1, struct path *p2)
static inline bool fanotify_fsid_equal(__kernel_fsid_t *fsid1,
__kernel_fsid_t *fsid2)
{
- return fsid1->val[0] == fsid1->val[0] && fsid2->val[1] == fsid2->val[1];
+ return fsid1->val[0] == fsid2->val[0] && fsid1->val[1] == fsid2->val[1];
}
static bool fanotify_fh_equal(struct fanotify_fh *fh1,