sched: Avoid printing sched_group::__cpu_power for default case
Commit 46e0bb9c12f4 ("sched: Print sched_group::__cpu_power
in sched_domain_debug") produces a messy dmesg output while
attempting to print the sched_group::__cpu_power for each
group in the sched_domain hierarchy.
Fix this by avoid printing the __cpu_power for default cases.
(i.e, __cpu_power == SCHED_LOAD_SCALE).
[ Impact: reduce syslog clutter ]
Reported-by: Tony Luck <tony.luck@intel.com>
Signed-off-by: Gautham R Shenoy <ego@in.ibm.com>
Fixed-by: Tony Luck <tony.luck@intel.com>
Cc: a.p.zijlstra@chello.nl
LKML-Reference: <20090414033936.GA534@in.ibm.com>
Signed-off-by: Ingo Molnar <mingo@elte.hu>
diff --git a/kernel/sched.c b/kernel/sched.c
index e90e70e..b902e58 100644
--- a/kernel/sched.c
+++ b/kernel/sched.c
@@ -7367,8 +7367,12 @@
cpumask_or(groupmask, groupmask, sched_group_cpus(group));
cpulist_scnprintf(str, sizeof(str), sched_group_cpus(group));
- printk(KERN_CONT " %s (__cpu_power = %d)", str,
- group->__cpu_power);
+
+ printk(KERN_CONT " %s", str);
+ if (group->__cpu_power != SCHED_LOAD_SCALE) {
+ printk(KERN_CONT " (__cpu_power = %d)",
+ group->__cpu_power);
+ }
group = group->next;
} while (group != sd->groups);