Fix "check_slabp" printout size calculation
We want to use the "struct slab" size, not the size of the pointer to
same. As it is, we'd not print out the last <n> entry pointers in the
slab (where <n> is ~10, depending on whether it's a 32-bit or 64-bit
kernel).
Gaah, that slab code was written by somebody who likes unreadable crud.
Signed-off-by: Linus Torvalds <torvalds@osdl.org>
diff --git a/mm/slab.c b/mm/slab.c
index add05d8..2b0b151 100644
--- a/mm/slab.c
+++ b/mm/slab.c
@@ -2554,7 +2554,7 @@
"slab: Internal list corruption detected in cache '%s'(%d), slabp %p(%d). Hexdump:\n",
cachep->name, cachep->num, slabp, slabp->inuse);
for (i = 0;
- i < sizeof(slabp) + cachep->num * sizeof(kmem_bufctl_t);
+ i < sizeof(*slabp) + cachep->num * sizeof(kmem_bufctl_t);
i++) {
if ((i % 16) == 0)
printk("\n%03x:", i);