[CRYPTO] Use standard byte order macros wherever possible
A lot of crypto code needs to read/write a 32-bit/64-bit words in a
specific gender. Many of them open code them by reading/writing one
byte at a time. This patch converts all the applicable usages over
to use the standard byte order macros.
This is based on a previous patch by Denis Vlasenko.
Signed-off-by: Herbert Xu <herbert@gondor.apana.org.au>
diff --git a/crypto/sha1.c b/crypto/sha1.c
index 4016f3b..c686e78 100644
--- a/crypto/sha1.c
+++ b/crypto/sha1.c
@@ -21,6 +21,7 @@
#include <linux/mm.h>
#include <linux/crypto.h>
#include <linux/cryptohash.h>
+#include <linux/types.h>
#include <asm/scatterlist.h>
#include <asm/byteorder.h>
@@ -72,20 +73,12 @@
static void sha1_final(void* ctx, u8 *out)
{
struct sha1_ctx *sctx = ctx;
- u32 i, j, index, padlen;
- u64 t;
- u8 bits[8] = { 0, };
+ __be32 *dst = (__be32 *)out;
+ u32 i, index, padlen;
+ __be64 bits;
static const u8 padding[64] = { 0x80, };
- t = sctx->count;
- bits[7] = 0xff & t; t>>=8;
- bits[6] = 0xff & t; t>>=8;
- bits[5] = 0xff & t; t>>=8;
- bits[4] = 0xff & t; t>>=8;
- bits[3] = 0xff & t; t>>=8;
- bits[2] = 0xff & t; t>>=8;
- bits[1] = 0xff & t; t>>=8;
- bits[0] = 0xff & t;
+ bits = cpu_to_be64(sctx->count);
/* Pad out to 56 mod 64 */
index = (sctx->count >> 3) & 0x3f;
@@ -93,16 +86,11 @@
sha1_update(sctx, padding, padlen);
/* Append length */
- sha1_update(sctx, bits, sizeof bits);
+ sha1_update(sctx, (const u8 *)&bits, sizeof(bits));
/* Store state in digest */
- for (i = j = 0; i < 5; i++, j += 4) {
- u32 t2 = sctx->state[i];
- out[j+3] = t2 & 0xff; t2>>=8;
- out[j+2] = t2 & 0xff; t2>>=8;
- out[j+1] = t2 & 0xff; t2>>=8;
- out[j ] = t2 & 0xff;
- }
+ for (i = 0; i < 5; i++)
+ dst[i] = cpu_to_be32(sctx->state[i]);
/* Wipe context */
memset(sctx, 0, sizeof *sctx);