HID: the `bit' in hidinput_mapping_quirks() is an out parameter
Fix a panic, by changing
hidinput_mapping_quirks(,, unsigned long *bit,)
to
hidinput_mapping_quirks(,, unsigned long **bit,)
The `bit' in this function is an out parameter.
Signed-off-by: Fengguang Wu <wfg@mail.ustc.edu.cn>
Signed-off-by: Andrew Morton <akpm@linux-foundation.org>
Signed-off-by: Jiri Kosina <jkosina@suse.cz>
diff --git a/include/linux/hid.h b/include/linux/hid.h
index 24f04cd..6a70b78 100644
--- a/include/linux/hid.h
+++ b/include/linux/hid.h
@@ -526,7 +526,7 @@
int hid_set_field(struct hid_field *, unsigned, __s32);
int hid_input_report(struct hid_device *, int type, u8 *, int, int);
int hidinput_find_field(struct hid_device *hid, unsigned int type, unsigned int code, struct hid_field **field);
-int hidinput_mapping_quirks(struct hid_usage *, struct input_dev *, unsigned long *, int *);
+int hidinput_mapping_quirks(struct hid_usage *, struct input_dev *, unsigned long **, int *);
void hidinput_event_quirks(struct hid_device *, struct hid_field *, struct hid_usage *, __s32);
int hidinput_apple_event(struct hid_device *, struct input_dev *, struct hid_usage *, __s32);
void hid_input_field(struct hid_device *hid, struct hid_field *field, __u8 *data, int interrupt);