time: don't inline EXPORT_SYMBOL functions
How is the compiler even handling exported functions that are marked
inline? Anyway, these shouldn't be inline because of that, so remove
that marking.
Based on a larger patch by Mark Charlebois to get LLVM to build the
kernel.
Cc: Thomas Gleixner <tglx@linutronix.de>
Cc: Mark Charlebois <mcharleb@qualcomm.com>
Cc: Paul Gortmaker <paul.gortmaker@windriver.com>
Cc: hank <pyu@redhat.com>
Cc: John Stultz <john.stultz@linaro.org>
Signed-off-by: Greg Kroah-Hartman <gregkh@linuxfoundation.org>
Signed-off-by: Andrew Morton <akpm@linux-foundation.org>
Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>
diff --git a/kernel/time.c b/kernel/time.c
index c2a27dd..f8342a4 100644
--- a/kernel/time.c
+++ b/kernel/time.c
@@ -240,7 +240,7 @@
* Avoid unnecessary multiplications/divisions in the
* two most common HZ cases:
*/
-inline unsigned int jiffies_to_msecs(const unsigned long j)
+unsigned int jiffies_to_msecs(const unsigned long j)
{
#if HZ <= MSEC_PER_SEC && !(MSEC_PER_SEC % HZ)
return (MSEC_PER_SEC / HZ) * j;
@@ -256,7 +256,7 @@
}
EXPORT_SYMBOL(jiffies_to_msecs);
-inline unsigned int jiffies_to_usecs(const unsigned long j)
+unsigned int jiffies_to_usecs(const unsigned long j)
{
#if HZ <= USEC_PER_SEC && !(USEC_PER_SEC % HZ)
return (USEC_PER_SEC / HZ) * j;